STPS3030CG STMicroelectronics

STPS3030/CT/CG/CR Low drop power Schottky rectifier Main product characteristics A1 I 2 x 15 A K F(AV) V 30 V RRM A2 T (max) 150 C j K V (max) 0.42 V F Features and benefits A2 Very small conduction losses A2 K Negligible switching losses A1 A1 Extremely fast switching 2 D PAK TO-220AB Low forward voltage drop for higher efficiency STPS3030CG STPS3030CT Low thermal resistance Avalanche capability specified Description Dual Schottky rectifier suited for switch mode A2 power supply and high frequency DC to DC K A1 converters. 2 I PAK 2 2 Packaged in TO-220AB, D PAK and I PAK, this STPS3030CR device is intended for use in low voltage high frequency inverters, free-wheeling and polarity j protection applications. October 2006 Rev 4 1/9 www.st.com 9Characteristics STPS3030CT/CG/CR 1 Characteristics Table 1. Absolute ratings (limiting values, per diode) Symbol Parameter Value Unit V Repetitive peak reverse voltage 30 V RRM I RMS forward current 30 A F(RMS) T = 135 C Per diode 15 c I Average forward current A F(AV) = 0.5 Per device 30 I Surge non repetitive forward current t = 10 ms sinusoidal 250 A FSM p I Peak repetitive reverse current t = 2 s square F= 1 kHz 1 A RRM p I Non repetitive peak reverse current t = 100 s square 3 A RSM p P Repetitive peak avalanche power t = 1 s T = 25 C 4100 W ARM p j T Storage temperature range -65 to + 150 C stg (1) T Maximum operating junction temperature 150 C j dV/dt Critical rate of rise of reverse voltage (rated V , T = 25 C) 10000 V/s R j dPtot 1 --------------- -------------------------- 1. < condition to avoid thermal runaway for a diode on its own heatsink dTj Rth()j a Table 2. Thermal resistance Symbol Parameter Value Unit Per diode 1.2 2 2 R Junction to case TO-220AB - D PAK - I PAK th(j-c) Total 0.8 C/W R Coupling 0.4 th(c) Table 3. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C 0.23 1.0 j (1) I Reverse leakage current V = V mA R R RRM T = 125 C 125 180 j T = 25 C I = 15 A 0.44 0.49 j F T = 125 C I = 15 A 0.36 0.40 j F (1) V Forward voltage drop V F T = 25 C I = 30 A 0.53 0.58 j F T = 125 C I = 30 A 0.49 0.53 j F 1. Pulse test: tp = 380 s, < 2% To evaluate the conduction losses use the following equation: 2 P = 0.26 x I + 0.0107 I F(AV) F (RMS) 2/9