STPS3L25S STMicroelectronics

STPS3L25S LOW DROP POWER SCHOTTKY RECTIFIER MAIN PRODUCT CHARACTERISTICS I 3A F(AV) V 25 V RRM Tj (max) 150C V (max) 0.44 V F FEATURES AND BENEFITS n VERY LOW FORWARD VOLTAGE DROP FOR LESS POWER DISSIPATION SMC n OPTIMIZED CONDUCTION/REVERSE LOSSES JEDEC DO-214AB TRADE-OFF WHICH MEANS THE HIGHEST EFFICIENCY IN THE APPLICATIONS n HIGH POWER SURFACE MOUNT MINIATURE PACKAGE n AVALANCHE CAPABILITY SPECIFIED DESCRIPTION Single Schottky rectifier suited to Switched Mode Power Supplies and high frequency DC to DC con- verters. Packaged in SMC, this device is especially in- tended for use as an antiparallel diode on synchro- nous rectification freewheel MOSFETs at the secondary of 3.3V SMPS and DC/DC units. ABSOLUTE RATINGS (limiting values) Symbol Parameter Value Unit V Repetitive peak reverse voltage 25 V RRM I RMS forward current 10 A F(RMS) I Average forward current T = 115C = 0.5 3 A F(AV) L I Surge non repetitive forward current tp = 10 ms Sinusoidal 75 A FSM I Repetitive peak reverse current tp= 2 s square F=1kHz 1 A RRM I Non repetitive peak reverse current tp = 100 s square 1 A RSM T Storage temperature range - 65 to + 150 C stg P Repetitive peak avalanche power tp = 1s Tj = 25C 1500 W ARM Tj Maximum operating junction temperature * 150 C dV/dt Critical rate of rise of reverse voltage 10000 V/s dPtot 1 *: < thermal runaway condition for a diode on its own heatsink dTj Rth()j - a July 2003 - Ed: 4A 1/4STPS3L25S THERMAL RESISTANCES Symbol Parameter Value Unit R Junction to lead 20 C/W th(j-l) STATIC ELECTRICAL CHARACTERISTICS Symbol Tests Conditions Tests Conditions Min. Typ. Max. Unit I * Reverse leakage current Tj = 25CV =V 90 A R R RRM Tj = 125C1530mA V * Forward voltage drop Tj = 25CI = 3 A 0.49 V F F Tj = 125C 0.37 0.44 Tj=25CI = 6 A 0.6 F Tj = 125C 0.5 0.58 Pulse test: * tp = 380 s, <2% To evaluate the maximum conduction losses use the following equation : 2 P=0.3 xI + 0.047 I F(AV) F (RMS) Fig. 1: Average forward power dissipation versus Fig. 2: Average forward current versus ambient average forward current. temperature (=0.5). PF(av)(W) IF(av)(A) 3.5 2.2 = 0.1 = 0.2 Rth(j-a)=Rth(j-l) = 0.5 2.0 = 0.05 3.0 1.8 2.5 1.6 = 1 1.4 2.0 1.2 Rth(j-a)=90C/W 1.0 1.5 0.8 1.0 T T 0.6 0.4 0.5 =tp/T tp tp Tamb(C) 0.2 =tp/T IF(av) (A) 0.0 0.0 0 25 50 75 100 125 150 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 2/5