STPS1L30M LOW DROP POWER SCHOTTKY RECTIFIER Table 1: Main Product Characteristics I 1 A F(AV) V 30 V RRM A T (max) 150C j V (max) C 0.38 V F FEATURES AND BENEFITS STmite (DO216-AA) Very small conduction losses Negligible switching losses Extremely fast switching Low forward voltage drop for higher efficiency and extented battery life Low thermal resistance Table 2: Order Code Avalanche capability specified Part Number Marking STPS1L30M 1L3 DESCRIPTION Single Schottky rectifier suited for switch mode power supplies and high frequency DC to DC converters. Packaged in STmite, this device is intended for use in low voltage, high frequency inverters, free wheeling and polarity protection applications. Due to the small size of the package this device fits battery powered equipment (cellular, notebook, PDAs, printers) as well chargers and PCMCIA cards. Table 3: Absolute Ratings (limiting values) Symbol Parameter Value Unit V Repetitive peak reverse voltage 30 V RRM I RMS forward voltage 2 A F(RMS) I T = 140C = 0.5 Average forward current 1A F(AV) c I Surge non repetitive forward current 10 ms sinusoidal 50 A FSM P Repetitive peak avalanche power tp = 1s Tj = 25C 1200 W ARM T Storage temperature range -65 to + 150 C stg T Maximum operating junction temperature * 150 C j Critical rate of rise of reverse voltage (rated V , T = 25C) dV/dt 10000 V/s R j dPtot 1 * : --------------- > -------------------------- thermal runaway condition for a diode on its own heatsink dTj Rth()j a September 2004 REV. 3 1/6STPS1L30M Table 4: Thermal Resistance Symbol Parameter Value Unit R * Junction to case 20 C/W th(j-c) R * Junction to ambient C/W 250 th(j-l) * Mounted with minimum recommended pad size, PC board FR4. Table 5: Static Electrical Characteristics Symbol Parameter Tests conditions Min. Typ Max. Unit T = 25C 0.13 0.39 j V = V R RRM T = 85C 5.25 16.5 j T = 25C V = 20V 0.05 0.24 j R I * Reverse leakage current mA R T = 85C 3.5 10.5 j T = 25C V = 10V 0.03 0.15 j R T = 85C 2.4 7 j T = 25C 0.33 0.39 j I = 1A F T = 85C 0.28 0.34 j V * Forward voltage drop V F T = 25C 0.45 0.53 j I = 3A F T = 85C 0.43 0.51 j Pulse test: * tp = 380 s, < 2% 2 To evaluate the conduction losses use the following equation: P = 0.34 x I + 0.07 I F(AV) F (RMS) Figure 1: Conduction losses versus average Figure 2: Average forward current versus current ambient temperature ( = 0.5) I (A) P (W) F(AV) F(AV) 1.1 0.50 R=th(j-a)Rth(j-c) = 0.1 = 0.2 = 0.5 = 0.05 1.0 0.45 0.9 0.40 = 1 0.8 0.35 0.7 0.30 Rth(j-a)=270C/W 0.6 0.25 0.5 0.20 0.4 0.15 0.3 T 0.10 0.2 0.05 0.1 I (A) F(AV) T (C) amb tp =tp/T 0.00 0.0 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3 0 25 50 75 100 125 150 2/6