STPS30H60CG-TR STMicroelectronics

STPS30H60C Power Schottky rectifier Features High junction temperature capability A1 Avalanche rated K Low leakage current A2 A2 K Good trade-off between leakage current and A1 forward voltage drop TO-220FPAB High frequency operation STPS30H60CFP Description Dual centre tab Schottky rectifier suited for high frequency switch mode power supply. A2 Packaged in TO-220FPAB, TO-220AB, TO-247, A2 K 2 2 K A1 I PAK, and D PAK, this device is intended to be A1 2 used in notebook and LCD adaptors and desktop TO-220AB I PAK SMPS. In these applications the STPS30H60C STPS30H60CT STPS30H60CR provides a good margin between the remaining voltages applied on the diode and the voltage capability of the diode. K A2 A1 A2 K A1 2 TO-247 D PAK STPS30H60CW STPS30H60CG Table 1. Device summary Symbol Value I 2 X 15 A F(AV) V 60 V RRM T 175 C j V 0.535 V F (typ) July 2011 Doc ID 12123 Rev 3 1/11 www.st.com 11Characteristics STPS30H60C 1 Characteristics Table 2. Absolute ratings (limiting values per diode) Symbol Parameter Value Unit V Repetitive peak reverse voltage 60 V RRM I Forward rms current 30 A F(RMS) Per diode 15 TO-220AB A T = 155 C c Total package 30 TO-220FPAB I Average forward current, = 0.5 Per diode 15 F(AV) T = 125 C c A TO-220FPAB Total package 30 T = 90 C c I Surge non repetitive forward current t = 10 ms sinusoidal 230 A FSM p P Releative peak avalanche power T = 25 C t = 1 s 10 200 W ARM j p T Storage temperature range -65 to + 175 C stg (1) T Maximum operating junction temperature 175 C j 1 dPtot < 1. condition to avoid thermal runaway for a diode on its own heatsink Rth(j-a) dTj Table 3. Thermal parameters Symbol Parameter Value Unit 2 Per diode 1.5 TO-220AB, I PAK, 2 D PAK, TO-247 Total 0.8 R Junction to case th(j-c) Per diode 4.7 TO-220FPAB C/W Total 3.95 2 2 TO-220AB, I PAK, D PAK, TO-247 0.1 R Coupling th(c) TO-220FPAB 3.2 Table 4. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C 60 A j (1) I Reverse leakage current V = V R R RRM mA T = 125 C 8 25 j T = 25 C 550 j I = 7.5 A F T = 125 C 435 470 j T = 25 C 660 j (2) V Forward voltage drop I = 15 A mV F F T = 125 C 535 570 j T = 25 C 820 j I = 30 A F T = 125 C 635 690 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p 2 To evaluate the conduction losses use the following equation: P = 0.45 x I + 0.008 x I F(AV) F (RMS) 2/11 Doc ID 12123 Rev 3