STPS40150C Datasheet 150 V power Schottky rectifier Features A1 K A2 High junction temperature capability Low leakage current High voltage capabilities Good trade off between leakage current and forward voltage drop Low thermal resistance A2 A2 High frequency operation K A1 K TO-220AB A1 TO-247 ECOPACK 2 compliant for TO-220AB and TO-247, on demand for DPAK K Applications Switching diode A2 DPAK A1 SMPS DC/DC converter Telecom power Description This dual center tab Schottky rectifier is suited for high frequency switched mode power supplies. 2 Packaged in TO-247, TO-220AB and D PAK, this STPS40150C is optimized for use to enhance the reliability of the application. Product status STPS40150C Product summary I 2 x 20 A F(AV) V 150 V RRM T 175 C j(max.) V 0.69 V F(typ.) DS3262 - Rev 2 - June 2018 www.st.com For further information contact your local STMicroelectronics sales office.STPS40150C Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values, per diode at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 150 V RRM I Forward rms current 60 A F(RMS) T = 150 C Per diode 20 C I Average forward current, = 0.5, square wave A F(AV) T = 145 C Per device 40 C I Surge non repetitive forward current t = 10 ms sinusoidal 250 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 1015 W ARM p j T Storage temperature range -65 to +175 C stg (1) T +175 C j Maximum operating junction temperature 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameters Value Symbol Parameter Unit Max. Per diode 1.20 R Junction to case C/W th(j-c) Total 0.85 R Coupling 0.50 C/W th(c) When the diodes 1 and 2 are used simultaneously: T = P x R (per diode) + P x R j (diode1) (diode1) th(j-c) (diode2) th(c) Table 3. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 2 8 A j (1) I Reverse leakage current V = V R RRM R T = 125 C - 2 11 mA j T = 25 C - 0.92 j I = 20 A F T = 125 C - 0.69 0.75 j (2) V Forward voltage drop V F T = 25 C - 1.00 j I = 40 A F T = 125 C - 0.79 0.86 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t =380 s, < 2% p 2 To evaluate the conduction losses, use the following equation: P = 0.64 x I + 0.0055 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses : AN604: Calculation of conduction losses in a power rectifier AN4021: Calculation of reverse losses on a power diode DS3262 - Rev 2 page 2/15