STPS140Z STMicroelectronics

STPS140Z POWER SCHOTTKY RECTIFIER MAIN PRODUCT CHARACTERISTICS I 1A F V 40 V RRM V (max) 0.49 V F Tj (max) 150C FEATURES AND BENEFITS n VERY SMALL CONDUCTION LOSSES n NEGLIGIBLE SWITCHING LOSSES SOD-123 n EXTREMELY FAST SWITCHING DESCRIPTION Single Schottky rectifier suited for Switchmode Power Supplies and high frequency DC to DC con- verters. Packaged in SOD-123, this device is intended for use in low voltage, high frequency inverters, free wheeling and polarity protection applications. Due to the small size of the package this device fit GSM and PCMCIA requirements. ABSOLUTE RATINGS (limiting values) Symbol Parameter Value Unit V Repetitive peak reverse voltage 40 V RRM I Continuous forward current T =60C 1 A F amb I Surge non repetitive forward current tp = 10 ms 5.5 A FSM Sinusoidal I Repetitive peak reverse current tp = 2 s square 0.5 A RRM F = 1kHz I Non repetitive peak reverse current tp = 100s square 1 A RSM T Storage temperature range - 65 to + 150 C stg Tj Maximum operating junction temperature * 150 T Maximum temperature for soldering during 10s 260 C L dV/dt Critical rate of rise of reverse voltage 10000 V/s dPtot 1 *: < thermal runaway condition for a diode on its own heatsink dTj Rth()j - a January 2002 - Ed: 1B 1/5STPS140Z THERMAL RESISTANCES Symbol Parameter Value Unit R Junction to ambient * 175 C/W th (j-a) 2 * with 50 mm copper area (e=35m) STATIC ELECTRICAL CHARACTERISTICS Symbol Tests Conditions Tests Conditions Min. Typ. Max. Unit I * Reverse leakage current Tj = 25C V =5V 10 A R R Tj=25CV = 40V 40 A R Tj = 100C 1.5 5 mA V ** Forward voltage drop Tj = 25CI = 1 A 0.55 V F F Tj = 100C 0.45 0.51 Pulse test : * tp=5ms, <2% ** tp = 380 s, <2% To evaluate the maximum conduction losses use the following equation : 2 P=0.2xI +0.3xI at Tj = 150C F(AV) F (RMS) Fig. 1: Average forward power dissipation versus Fig. 2: Average forward current versus ambient average forward current. temperature (=1). PF(av)(W) IF(av)(A) 0.6 1.2 = 0.1 = 0.2 = 0.5 = 0.05 0.5 1.0 0.4 0.8 = 1 0.3 0.6 0.2 0.4 T T 0.2 0.1 Tamb(C) IF(av) (A) =tp/T tp =tp/T tp 0.0 0.0 0 25 50 75 100 125 150 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 2/5