STPS2H100 Datasheet 100 V, 2 A power Schottky rectifier Features Negligible switching losses High junction temperature capability Low leakage current Good trade-off between leakage current and forward voltage drop Avalanche capability specified ECOPACK2 component Applications Switching diode Battery charger SMPS DC / DC converter Telecom power LED lighting Description This Schottky rectifier is designed for high frequency miniature switched mode power supplies such as adaptors and on board DC/DC converters. Packaged in SMA, SMA Flat, SMB, SMB Flat and SMA Flat Notch, the STPS2H100 Product status link is ideal for use in lighting and telecom power applications. STPS2H100 Product summary Symbol Value I F(AV) 2 A V 100 V RRM T (max.) 175 C j V (max.) 0.65 V F DS1452 - Rev 10 - October 2019 www.st.com For further information contact your local STMicroelectronics sales office.STPS2H100 Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 100 V RRM T = 130 C, = 0.5 SMA l T = 135 C, = 0.5 SMB l I Average forward current 2 A F(AV) T = 145 C, = 0.5 SMA Flat, SMA Flat Notch l SMB Flat T = 150 C, = 0.5 l I Surge non repetitive forward current t = 10 ms sinusoidal 75 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 173 W ARM p j T Storage temperature range -65 to +175 C stg (1) T Maximum operating junction temperature 175 C j 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameters Symbol Parameter Max. value Unit SMA 30 SMA Flat, SMA Flat Notch 20 R Junction to lead C/W th(j-l) SMB 25 SMB Flat 15 For more information, please refer to the following application note : AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 1.00 A j (1) I V = V Reverse leakage current R R RRM T = 125 C - 0.40 1.00 mA j T = 25 C - 0.79 j I = 2 A F T = 125 C - 0.60 0.65 j (2) V Forward voltage drop V F T = 25 C - 0.88 j I = 4 A F T = 125 C - 0.69 0.74 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.56 x I + 0.045 x I F(AV) F (RMS) DS1452 - Rev 10 page 2/19