STPS2L25 Datasheet 25 V, 2 A low drop power Schottky rectifier Features Very low forward voltage drop for less power dissipation Optimized conduction/reverse losses trade-off which means the highest efficiency in the applications Avalanche rated ECOPACK2 compliant Applications Cordless appliance SSD Battery charger Telecom power DC / DC converter Description Schottky rectifiers designed for high frequency miniature switched mode power supplies such as adaptors and on board DC/DC converters. Packaged in SMA Flat Notch or SMB for thermal resistance characteristic improvement, the STPS2L25 is ideal for use in parallel with MOSFETs in synchronous rectification. Product status STPS2L25 Product summary Symbol Value I F(AV) 2 A V 25 V RRM T 150 C j(max.) V 0.325 V F(typ.) DS1245 - Rev 7 - September 2019 www.st.com For further information contact your local STMicroelectronics sales office.STPS2L25 Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 25 V RRM I Forward rms current 10 A F(RMS) T = 125 C SMB L I Average forward current, = 0.5 square wave 2 A F(AV) T = 130 C SMA Flat Notch L SMB 75 I Surge non repetitive forward current t = 10 ms sinusoidal A FSM p SMA Flat Notch 90 P t = 10 s, T = 125 C Repetitive peak avalanche power 108 W ARM p j T Storage temperature range -65 to +150 C stg (1) T +150 C j Maximum operating junction temperature 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameter Symbol Parameter Max. value Unit SMB 25 R Junction to lead C/W th(j-l) SMA Flat Notch 20 For more information, please refer to the following application note : AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 90 A j (1) I Reverse leakage current V = V R RRM R T = 125 C - 15 30 mA j T = 25 C - 0.450 j I = 2 A F T = 125 C - 0.325 0.375 j (1) V Forward voltage drop V F T = 25 C - 0.530 j I = 4 A F T = 125 C - 0.430 0.510 j 1. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.24 x I + 0.068 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses : AN604: Calculation of conduction losses in a power rectifier AN4021: Calculation of reverse losses on a power diode DS1245 - Rev 7 page 2/12