STPS3H100UFN Datasheet 100 V, 3 A Schottky rectifier Features Negligible switching losses High junction temperature capability Low leakage current Good trade-off between leakage current and forward voltage drop Avalanche capability specified ECOPACK2 compliant Applications Switching diode Notebook adapter LED lighting DC/DC converter Description This high voltage Schottky barrier rectifier device is packaged in SMB Flat Notch and designed for high frequency miniature switched mode power supplies and for board DC to DC converters. Product status link STPS3H100UFN Product summary I 3 A F(AV) V 100 V RRM T (max.) 175 C j V (typ.) 0.57 V F DS13089 - Rev 1 - January 2020 www.st.com For further information contact your local STMicroelectronics sales office.STPS3H100UFN Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 100 V RRM I T = 140 C Average forward current, = 0.5 square wave 3 A F(AV) l I t = 10 ms sinusoidal Surge non repetitive forward current 135 A FSM p t = 10 s, p P Repetitive peak avalanche power 170 W ARM T = 125 C j T Storage temperature range -65 to +175 C stg (1) T -40 to +175 C j Maximum operating junction temperature range 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameter Symbol Parameter Max. value Unit R Junction to lead 15 C/W th(j-l) For more information, please refer to the following application note: AN5088: Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 1.5 A j (1) I V = V Reverse leakage current R R RRM T = 125 C - 0.6 1.7 mA j T = 25 C - 0.76 j I = 3 A F T = 125 C - 0.57 0.61 j (2) V Forward voltage drop V F T = 25 C - 0.84 j I = 6 A F T = 125 C - 0.64 0.68 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.54 x I + 0.023 x I F(AV) F (RMS) For more information, please refer to the following application notes related to the power losses : AN604: Calculation of conduction losses in a power rectifier AN4021: Calculation of reverse losses on a power diode DS13089 - Rev 1 page 2/9