STPS20120C Power Schottky rectifier Datasheet - production data Description This dual diode Schottky rectifier is suited for high . frequency switched mode power supplies. Packaged in DPAK, TO-220AB, TO-220AB narrow leads and IPAK, this device is intended to be used in notebook and LCD adaptors, desktop SMPS, providing in these applications a margin between the remaining voltages applied on the diode and the voltage capability of the diode . Table 1. Device summary 2 % QDUURZ OHDGV 7 . ,3 Symbol Value . I 2 X 10 A F(AV) V 120 V RRM T (max) 175 C j V (typ) 0.70 V F . 2 % 7 . 3 Features High junction temperature capability Good trade-off between leakage current and forward voltage drop Low leakage current Avalanche capability specified ECOPACK 2 compliant component for DPAK on demand November 2016 DocID11212 Rev 4 1/14 This is information on a product in full production. www.st.comCharacteristics STPS20120C 1 Characteristics Table 2. Absolute ratings (limiting values per diode at T = 25 C unless otherwise stated) amb Symbol Parameter Value Unit V Repetitive peak reverse voltage 120 V RRM I Forward rms current 30 A F(RMS) T = 150 C per diode 10 c Average forward current, I A F(AV) = 0.5, square wave T = 145 C per device 20 c I Surge non repetitive forward current t = 10 ms sinusoidal 150 A FSM p P Repetitive peak avalanche power t = 10 s, T = 125 C 330 W ARM p j T Storage temperature range -65 to +175 C stg (1) T Maximum operating junction temperature 175 C j dPtot 1 1. condition to avoid thermal runaway for a diode on its own heatsink < Rth(j-a) dTj Table 3. Thermal parameters Symbol Parameter Max. value Unit per diode 3 R Junction to case th(j-c) total 1.8 C/W R Coupling 0.6 th(c) When the two diodes 1 and 2 are used simultaneously: T (diode1) = P(diode1) x R (per diode) + P(diode2) x R j th(j-c) th(c) Table 4. Static electrical characteristics (per diode) Symbol Parameter Test conditions Min. Typ Max. Unit T = 25 C -10A j (1) I Reverse leakage current V = V R R RRM T = 125 C - 1.5 5 mA j T = 25 C -0.70 j I = 2.5 A F T = 125 C - 0.54 0.58 j T = 25 C -0.92 j (2) V Forward voltage drop I = 10 A V F F T = 125 C - 0.70 0.74 j T = 25 C -1.02 j I = 20 A F T = 125 C - 0.81 0.86 j 1. Pulse test: t = 5 ms, < 2% p 2. Pulse test: t = 380 s, < 2% p To evaluate the conduction losses, use the following equation: 2 P = 0.62 x I + 0.012 x I F(AV) F (RMS) 2/14 DocID11212 Rev 4