STPS2L60 Datasheet 60 V, 2 A low drop power Schottky rectifier Features Negligible switching losses Low forward voltage drop for higher efficiency and extended battery life Surface mount miniature package Avalanche rated ECOPACK2 compliant component Applications Lighting Desktop power supply Battery charger Set top box Auxiliary power Description This 60 V power Schottky rectifier is ideal for switch mode power supplies and high frequency converters. Packaged in SMA, SMA Flat Notch, axial and SMB Flat, the STPS2L60 is optimized for use in low voltage, high frequency inverters and small battery chargers. Product status STPS2L60 Product summary Symbol Values I F(AV) 2 A V 60 V RRM T 150 C j (max.) V 0.51 V F(typ.) DS2976 - Rev 8 - September 2019 www.st.com For further information contact your local STMicroelectronics sales office.STPS2L60 Characteristics 1 Characteristics Table 1. Absolute ratings (limiting values, at 25 C, unless otherwise specified) Symbol Parameter Value Unit V Repetitive peak reverse voltage 60 V RRM I Forward rms current 10 A F(RMS) T = 130 C SMB Flat L T = 115 C SMA L Average forward current I 2 A F(AV) = 0.5, square wave SMA Flat Notch T = 120 C L DO-41 T = 110 C L Surge non repetitive SMB Flat, SMA, I 75 FSM forward current DO-41 t = 10 ms sinusoidal p A SMA Flat Notch 105 Repetitive peak avalanche P t = 10 s, T = 125 C 115 W ARM p j power T Storage temperature range -65 to + 150 C stg (1) T + 150 C j Maximum operating junction temperature 1. (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 2. Thermal resistance parameter Symbol Parameter Max. value Unit SMB Flat 15 Junction to lead SMA 25 R C/W th(j-l) SMA Flat Notch 20 Junction to lead Lead length = 10 mm DO-41 30 For more information, please refer to the following application note : AN5088 : Rectifiers thermal management, handling and mounting recommendations Table 3. Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 100 A j Reverse leakage (1) I V = V R RRM R current T = 100 C - 2 10 mA j T = 25 C - 0.60 j I = 2 A F T = 125 C - 0.51 0.55 j Forward voltage (1) V V F drop T = 25 C - 0.77 j I = 4 A F T = 125 C - 0.62 0.67 j 1. Pulse test: t = 380 s, < 2% p 2 To evaluate the conduction losses use the following equation: P = 0.43 x I + 0.06 I F(AV) F (RMS) DS2976 - Rev 8 page 2/15