STPS200170TV1 STMicroelectronics

STPS200170TV1 High voltage power Schottky rectifier Datasheet - production data Description A1 K1 This high voltage Schottky rectifier is suited for A2 K2 high frequency switch mode power supplies. Packaged in ISOTOP, this device is intended for A2 use in the secondary rectification of applications. K2 Table 1: Device summary A1 Symbol Value K1 IF(AV) 2 x 100 A ISOTOP VRRM 170 V T (max.) 150 C j VF (max.) 0.63 V Features Negligible switching losses Avalanche rated Low leakage current Good trade-off between leakage current and forward voltage drop Insulated package ISOTOP: Insulated voltage: 2500 V RMS Capacitance: 45 pF February 2018 DocID11857 Rev 3 1/8 www.st.com This is information on a product in full production. Characteristics STPS200170TV1 1 Characteristics Table 2: Absolute ratings (limiting values, per diode at Tamb = 25 C, unless otherwise specified) Symbol Parameter Value Unit VRRM Repetitive peak reverse voltage 170 V I Forward rms current 200 A F(RMS) T = 105 C Per diode IF(AV) Average forward current, = 0.5 C 100 A I Surge non repetitive forward current t = 10 ms sinusoidal 700 A FSM p P Repetitive peak avalanche power tp = 10 s Tj = 125 C 7400 W ARM Tstg Storage temperature range -55 to +150 C (1) Tj Maximum operating junction temperature 150 C Notes: (1) (dP /dT ) < (1/R ) condition to avoid thermal runaway for a diode on its own heatsink. tot j th(j-a) Table 3: Thermal parameters Symbol Parameter Maximum values Unit Per diode 0.52 Junction to case Rth(j-c) Total 0.31 C/W Coupling thermal resistance Rth(c) 0.1 When the diodes 1 and 2 are used simultaneously: T (diode1) = P x R + P x R j (diode1) th(j-c) (per diode) (diode2) th(c) Table 4: Static electrical characteristics Symbol Parameter Test conditions Min. Typ. Max. Unit T = 25 C - 200 A j (1) I Reverse leakage current V = V R R RRM Tj = 125 C - 30 100 mA T = 25 C - 0.85 j I = 100 A F Tj = 150 C - 0.63 0.68 (2) VF Forward voltage drop V T = 25 C - 0.975 j I = 200 A F Tj = 150 C - 0.78 0.86 Notes: (1) Pulse test: t = 5 ms, < 2% p (2) Pulse test: tp = 380 s, < 2% To evaluate the maximum conduction losses, use the following equation: 2 P = 0.5 x IF(AV) + 0.0018 x IF (RMS) 2/8 DocID11857 Rev 3